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i've never been a natural all i do is try, try, try Let f be the function defined by f(x) = sqrt(x+4). What is the approximation of sqrt(4.2) found by using the line tangent to the graph of f at x = 0? A. 2.05 B. 2.10 C. 2.25 D. 2.40 Focus on your questions Sovi.AI helps me break down the parts I don't understand so I can keep going Answer Only All Subjects Math History Step 1: Find the point of tangency We need to find the point on the graph of f(x) = sqrt(x+4) at x = 0. f(0) = sqrt(0+4) = sqrt(4) = 2 The point of tangency is (0, 2). Step 2: Find the derivative and slope We find the derivative of f(x) = (x+4)^(1/2) to determine the slope of the tangent line. f'(x) = 1/2(x+4)^(-1/2) = 1 / (2*sqrt(x+4)) m = f'(0) = 1 / (2*sqrt(0+4)) = 1 / (2*2) = 1/4 Step 3: Write the equation of the tangent line L(x) = 0.25(x) + 2 L(0.2) = 0.25(0.2) + 2 L(0.2) = 0.05 + 2 = 2.05 Answer: A Ask Expert Rare +++ Linear Approximation Local Ruler "Zoom in until it looks straight." Short Concept Summary Linear approximation uses the tangent line at a to approximate f(x) for x near a. Differentials describe small changes dx to approximate the change dy. Key Points - Tangent line L(x) approximates f(x) for x near a. - The differential dy approximates the change Ay. - Accuracy increases as x approaches the point of tangency.