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How high can John Walker jump in Thunderbolts? John Walker does this. Is an uninterrupted. We can actually calculate a lot of information from. First and foremost, we need the length of time that John Walker was air, which I measured software to be 6.87 seconds. And we need Earth's gravity, Earth's rate of which is 9.8 meters per second squared. To figure out spent going up and back down. Now, since this motion is perfectly symmetrical, we take his and divide it. Which means John Walker spent 3.435 seconds going up and 3.435 seconds going back down. So how fast gravity is going to remove 9.8 meters per second from his upward. So after 3.435 seconds, gravity has slowed him down to zero meters per second. Equation. Velocity under constant acceleration: v = v0 - gt. This equation for velocity under constant acceleration. At the top, v = 0. So 0 = v0 - gt. Now at the top, John's velocity is 0. So we substitute 0 for velocity in the equation. Rearrange: v0 = gt. Now we rearrange the equation by just adding g and t. Plug in numbers: v0 = 9.81 (3.435). v0 = 33.70 m/s. Zero and then in the numbers. Rate of gravity and the time he spent going. And we get 33.7 meters per second. But what does this mean? If his upward motion was 33.7 meters per second, that could be converted to 75.4 miles per hour. And with this, how high he jumped. His average speed is not 33.7. That's his starting speed. However, his ending speed at the jump is zero meters per second. We take the average of those two numbers and we get 16.85 meters per second. Average upward speed: 16.85 m/s. Multiply by how long you're rising: 16.85 x 3.435. Just take his average upward speed and multiply it by the time spent rising in the air. The result is 57.87 meters. And when we convert that to that John Walker jumped approximately 190 feet straight in the air. I googled 190 foot building and if you wanna see more breakdowns, go ahead and follow me.